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x^2-2.75x+.625=0
We add all the numbers together, and all the variables
x^2-2.75x+0.625=0
a = 1; b = -2.75; c = +0.625;
Δ = b2-4ac
Δ = -2.752-4·1·0.625
Δ = 5.0625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.75)-\sqrt{5.0625}}{2*1}=\frac{2.75-\sqrt{5.0625}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.75)+\sqrt{5.0625}}{2*1}=\frac{2.75+\sqrt{5.0625}}{2} $
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